hi guys, hope you can help me with 2 questions:

A- In the fraction x/y, where x and y are positive integers, what is the value of y?

1) the least common denominator of x/y and 1/3 is 6

2) x=1

B- If w,x,y,z are integers such that w/x and y/z are integers. is w/x + y/z odd?

1)wx + yz is odd

2)wz + xy is odd

OA for the first question is E and for the second B

## integers

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B does not help in any way to resolve y.

Put together, y could be 2 or 6. so E.

2) Divide the second expression by xz and you will get (w/x) + (y/z). Since, the expression given in B indicates it is odd, and the stem indicates that (w/x) and (y/z) are integers it must be true that (w/x) + (y/z) is an odd integer -- You divide an odd integer by another integer and the result is either an odd integer or a non-integer.

Hope this clarifies.

Can you please clarify how you derived the values of Y from the LCM?kris610 wrote:1) A indicates y could be 2 or 6. INSUFFICIENT.

B does not help in any way to resolve y.

Put together, y could be 2 or 6. so E.

Hope this clarifies.

--- A ---yakiraz wrote:hi guys, hope you can help me with 2 questions:

A- In the fraction x/y, where x and y are positive integers, what is the value of y?

1) the least common denominator of x/y and 1/3 is 6

2) x=1

B- If w,x,y,z are integers such that w/x and y/z are integers. is w/x + y/z odd?

1)wx + yz is odd

2)wz + xy is odd

OA for the first question is E and for the second B

Ans: E

In statement 1,

y can be either 6 or 2.

Calculate LCM of,

x/

**2**+ 1/3 = z/

**6**

Calculate LCM of,

x/6 + 1/3 = z/6

In both case we get the LCM of denominator to be 6.

so INSUFFICIENT

Statement 2 doesnt help much so INSUFFICIENT.